Random 是使用最广泛的随机数生成工具了,即使连 Math.random() 的底层也是用 Random 实现的Math.random() 源码如下:

可以看出 Math.random()直接指向了 Random.nextDouble()方法。
🤗 Random源码解析
/**
* Returns a pseudorandom, uniformly distributed {@code int} value
* between 0 (inclusive) and the specified value (exclusive), drawn from
* this random number generator's sequence. The general contract of
* {@code nextInt} is that one {@code int} value in the specified range
* is pseudorandomly generated and returned. All {@code bound} possible
* {@code int} values are produced with (approximately) equal
* probability.
*
* @implSpec The method {@code nextInt(int bound)} is implemented by
* class {@code Random} as if by:
* <pre>{@code
* public int nextInt(int bound) {
* if (bound <= 0)
* throw new IllegalArgumentException("bound must be positive");
*
* if ((bound & -bound) == bound) // i.e., bound is a power of 2
* return (int)((bound * (long)next(31)) >> 31);
*
* int bits, val;
* do {
* bits = next(31);
* val = bits % bound;
* } while (bits - val + (bound-1) < 0);
* return val;
* }}</pre>
*
* <p>The hedge "approximately" is used in the foregoing description only
* because the next method is only approximately an unbiased source of
* independently chosen bits. If it were a perfect source of randomly
* chosen bits, then the algorithm shown would choose {@code int}
* values from the stated range with perfect uniformity.
* <p>
* The algorithm is slightly tricky. It rejects values that would result
* in an uneven distribution (due to the fact that 2^31 is not divisible
* by n). The probability of a value being rejected depends on n. The
* worst case is n=2^30+1, for which the probability of a reject is 1/2,
* and the expected number of iterations before the loop terminates is 2.
* <p>
* The algorithm treats the case where n is a power of two specially: it
* returns the correct number of high-order bits from the underlying
* pseudo-random number generator. In the absence of special treatment,
* the correct number of <i>low-order</i> bits would be returned. Linear
* congruential pseudo-random number generators such as the one
* implemented by this class are known to have short periods in the
* sequence of values of their low-order bits. Thus, this special case
* greatly increases the length of the sequence of values returned by
* successive calls to this method if n is a small power of two.
*
* @param bound the upper bound (exclusive). Must be positive.
* @return the next pseudorandom, uniformly distributed {@code int}
* value between zero (inclusive) and {@code bound} (exclusive)
* from this random number generator's sequence
* @throws IllegalArgumentException if bound is not positive
* @since 1.2
*/
public int nextInt(int bound) {
// 验证边界的合法性
if (bound <= 0)
throw new IllegalArgumentException(BadBound);
// 根据老种子生成新种子
int r = next(31);
// 计算最大值
int m = bound - 1;
// 根据新种子计算随机数
if ((bound & m) == 0) // i.e., bound is a power of 2
r = (int)((bound * (long)r) >> 31);
else {
for (int u = r;
u - (r = u % bound) + m < 0;
u = next(31));
}
return r;
}从以上源码我们可以看出,整个源码最核心的部分有两块:
- 根据老种子生成新种子;
- 根据新种子计算出随机数。
根据新种子计算出随机数的代码已经很明确了,我们需要确认一下 next() 方法是如何实现的,继续看源码:
/**
* Generates the next pseudorandom number. This method returns an
* {@code int} value such that, if the argument {@code bits} is between
* {@code 1} and {@code 32} (inclusive), then that many low-order
* bits of the returned value will be (approximately) independently
* chosen bit values, each of which is (approximately) equally
* likely to be {@code 0} or {@code 1}.
*
* @apiNote
* The other random-producing methods in this class are implemented
* in terms of this method, so subclasses can override just this
* method to provide a different source of pseudorandom numbers for
* the entire class.
*
* @implSpec
* The implementation in this class atomically updates the seed to
* <pre>{@code (seed * 0x5DEECE66DL + 0xBL) & ((1L << 48) - 1)}</pre>
* and returns
* <pre>{@code (int)(seed >>> (48 - bits))}.</pre>
*
* <p>This is a linear congruential pseudorandom number generator, as
* defined by D. H. Lehmer and described by Donald E. Knuth in
* <cite>The Art of Computer Programming, Volume 2, Third edition:
* Seminumerical Algorithms</cite>, section 3.2.1.
*
* @param bits random bits
* @return the next pseudorandom value from this random number
* generator's sequence
* @since 1.1
*/
protected int next(int bits) {
long oldseed, nextseed;
AtomicLong seed = this.seed;
do {
oldseed = seed.get();
nextseed = (oldseed * multiplier + addend) & mask;
} while (!seed.compareAndSet(oldseed, nextseed));
return (int)(nextseed >>> (48 - bits));
}根据以上源码可以看出,在使用老种子去获取新种子的时候,如果是多线程操作,则同一时刻只会有一个线程 CAS (Conmpare And Swap,比较并交换) 成功,其他失败的线程会通过自旋等待获取新种子,因此会有一定的性能消耗。
这也是为什么 JDK 1.7 会引入 ThreadLocalRandom 的答案了,它的出现主要为了提升多线程情况下 Random 的执行效率。那它是如何来提升的?接下来一起来看。
🥳 ThreadLocalRandom使用
我们先来看 ThreadLocalRandom 的类关系图:

可以看出 ThreadLocalRandom 继承于 Random 类,先来看它的使用:
ThreadLocalRandom threadLocalRandom = ThreadLocalRandom.current();
for (int i = 0; i < 3; i++) {
// 生成 0-9 的随机数
System.out.println(threadLocalRandom.nextInt(10));
}🤔 ThreadLocalRandom源码解析
/**
* 源码版本:JDK 11 JDK17和JDK8是直接使用的父类的
*/
public int nextInt(int bound) {
if (bound <= 0)
throw new IllegalArgumentException(BAD_BOUND);
// 根据老种子生成新种子
int r = mix32(nextSeed());
int m = bound - 1;
// 根据新种子计算算出随机数
if ((bound & m) == 0) // power of two
r &= m;
else { // reject over-represented candidates
for (int u = r >>> 1;
u + m - (r = u % bound) < 0;
u = mix32(nextSeed()) >>> 1)
;
}
return r;
}
/**
* 源码版本:JDK 11
*/
final long nextSeed() {
Thread t; long r; // read and update per-thread seed
// 把当前线程作为参数生成一个新种子
U.putLong(t = Thread.currentThread(), SEED,
r = U.getLong(t, SEED) + GAMMA);
return r;
}
@HotSpotIntrinsicCandidate
public native void putLong(Object o, long offset, long x);从以上源码可以看出,ThreadLocalRandom 并不是像 Thread 那样使用 CAS 和自旋来获取新种子,而是在每个线程中使用每个线程中保存自己的老种子来生成新种子,因此就可以避免多线程竞争和自旋等待的时间,所以在多线程环境下性能更高。
🤥 ThreadLocalRandom 注意事项
在使用 ThreadLocalRandom 时需要注意一下,在多线程不能共享一个 ThreadLocalRandom 对象,否则会造成生成的随机数都相同,如下代码所示:
// 声明多线程
ExecutorService service = Executors.newCachedThreadPool();
// 共享 ThreadLocalRandom
ThreadLocalRandom threadLocalRandom = ThreadLocalRandom.current();
for (int i = 0; i < 10; i++) {
// 多线程执行随机数并打印结果
service.submit(() -> {
System.out.println(Thread.currentThread().getName() + ":" + threadLocalRandom.nextInt(10));
;
});
}😶🌫️ 性能对比
接下来我们使用 Oracle 官方提供的性能测试工具 JMH (Java Microbenchmark Harness,JAVA 微基准测试套件),来测试一下 Random 和 ThreadLocalRandom 的吞吐量(单位时间内成功执行程序的数量):
import org.openjdk.jmh.annotations.Benchmark;
import org.openjdk.jmh.annotations.BenchmarkMode;
import org.openjdk.jmh.annotations.Mode;
import org.openjdk.jmh.annotations.OutputTimeUnit;
import org.openjdk.jmh.runner.Runner;
import org.openjdk.jmh.runner.RunnerException;
import org.openjdk.jmh.runner.options.Options;
import org.openjdk.jmh.runner.options.OptionsBuilder;
import java.util.Random;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.ThreadLocalRandom;
import java.util.concurrent.TimeUnit;
/**
* JDK:11
* Windows 10 I5-4460/16G
*/
@BenchmarkMode(Mode.Throughput) // 测试类型:吞吐量
//@Threads(16)
@OutputTimeUnit(TimeUnit.MILLISECONDS)
public class RandomExample {
public static void main(String[] args) throws RunnerException {
// 启动基准测试
Options opt = new OptionsBuilder()
.include(RandomExample.class.getSimpleName()) // 要导入的测试类
.warmupIterations(5) // 预热 5 轮
.measurementIterations(10) // 度量10轮
.forks(1)
.build();
new Runner(opt).run(); // 执行测试
}
/**
* Random 性能测试
*/
@Benchmark
public void randomTest() {
Random random = new Random();
for (int i = 0; i < 10; i++) {
// 生成 0-9 的随机数
random.nextInt(10);
}
}
/**
* ThreadLocalRandom 性能测试
*/
@Benchmark
public void threadLocalRandomTest() {
ThreadLocalRandom threadLocalRandom = ThreadLocalRandom.current();
for (int i = 0; i < 10; i++) {
threadLocalRandom.nextInt(10);
}
}
}
测试结果如下:

其中,Cnt 表示运行了多少次,Score 表示执行的成绩,Units 表示每秒的吞吐量。
从 JMH 测试的结果可以看出,ThreadLocalRandom 在并发情况下的吞吐量约是 Random 的 5 倍。
📎 参考文章
- Java Random 随机算法解释
- 《Java 并发编程之美》翟陆续
- ThreadLocalRandom类原理剖析